71M6515H
A Maxim Integrated Products Brand
Energy Meter IC
? tan( φ S ) 1 + ( 1 ? 2 ? 9 ) 2 ? 2 ( 1 ? 2 ? 9 ) cos( 2 π f 0 T ) ] ?
[
]
? ( 1 ? 2 ) sin( 2 π f 0 T ) ? tan( φ S ) 1 ? ( 1 ? 2 ) cos( 2 π f 0 T ) ?
DATA SHEET
JULY 2011
We calculate PHADJ from φ S , the desired phase lag:
PHADJ = 2 20 ? ? 9 ? 9 ?
Finally, we calculate the new calibration current gain coefficient, including compensation for a slight gain increase in the phase
calibration circuit.
PHADJ ? 2 ( 1 ? 2 ? 9 ) cos( 2 π f 0 T ))
PHADJ ( 2 + 2
CAL _ I NEW =
CAL _ I
A XI
1 +
2
? 20
1
? 20
1 ? 2 ( 1 ? 2 ? 9 ) cos( 2 π f 0 T ) + ( 1 ? 2 ? 9 ) 2
Calibration with Five Measurements
The five measurement method provides more orthogonality between the gain and phase error derivations. This method
involves measuring E V , E 0 , E 180 , E 60 , and E 300 . Again, set all calibration factors to nominal, i.e. CAL_IA = 16384, CAL_VA =
16384, PHADJ_A = 0..
First, calculate A XV from E V :
1. ?
A XV = E V + 1
Calculate A XI from E 0 and E 180 :
2.
E 0 =
IV A XV A XI cos( 0 ? φ S )
IV cos( 0 )
? 1 = A XV A XI cos( φ S ) ? 1
3.
E 180 =
IV A XV A XI cos(180 ? φ S )
IV cos( 180 )
? 1 = A XV A XI cos( φ S ) ? 1
4.
E 0 + E 180 = 2 A XV A XI cos( φ S ) ? 2
5.
A XV A XI =
E 0 + E 180 + 2
2 cos( φ S )
6. ?
A XI =
( E 0 + E 180 ) 2 + 1
A XV cos( φ S )
Use above results along with E 60 and E 300 to calculate φ S .
7.
E 60 =
IV A XV A XI cos( 60 ? φ S )
IV cos( 60 )
? 1
= A XV A XI cos( φ S ) + A XV A XI tan( 60 ) sin( φ S ) ? 1
8.
E 300 =
IV A XV A XI cos( ? 60 ? φ S )
IV cos( ? 60 )
? 1
= A XV A XI cos( φ S ) ? A XV A XI tan( 60 ) sin( φ S ) ? 1
Page: 27 of 60
? 2005 ? 2011 Teridian Semiconductor Corporation
1.6
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